John Hatcliffe and Elizabeth Bratley

St Peter's Church, Asterby
cc-by-sa/2.0 - © Tony Atkin - geograph.org.uk/p/44351

John Hatcliffe (bap. 26 Feb 1786, in Asterby), son of Joseph and Mary Hatcliffe, married Elizabeth Bratley (bap. 2 Mar 1794 in Baumber), daughter of David and Margaret Bratley, on 27 Oct 1812, at St Peter's Church, Asterby, Lincolnshire. In fact, the marriage record lists her as Elizabeth Brattlea, but it's close enough!

The following ten children look likely to be theirs: 

1. Mary Hatcliffe bap. 1813 in Market Stainton, Lincolnshire
2. William Hatcliffe bap. 11 Jan 1815 in Panton, Lincolnshire
3. Jane Hatcliffe bap. 18 Mar 1817 in Panton, Lincolnshire
4. John Hatcliffe bap. 24 Sep 1820 in Panton, Lincolnshire
5. David Hatcliffe bap. 7 Oct 1821 in Panton, Lincolnshire
6. Amos Hatcliffe bap. 20 Oct 1823 at St Peter's Church, Asterby
7. Helvin Hatcliffe bap. 11 Apr 1825 at St Peter's Church, Asterby
8. Saul Hatcliffe bap. 26 Dec 1829 at St Peter's Church, Asterby
9. Job Hatcliffe bap. 25 Sep 1831 at St Peter's Church, Asterby
10. Barnabas Hatcliffe bap. 11 Aug 1833. Barney Hatcliffe died aged 3, and was buried on 7 Mar 1836, both events at St Peter's Church, Asterby

i. Makes sense as Market Stainton is only 4 miles from Baumber.

In 1841, living in Asterby, Lincolnshire, were John Hatcliffe (55) Agricultural Labourer, Elizabeth Hatcliffe (45), with sons John (20), Saul (11) and Job (9). 

John Hatcliffe died, at 66, and was buried, on 16 Feb 1851 at St Peter's, Asterby.

In 1861, Elizabeth Hatcliffe (68) Widow, Pauper, born in Baumber, Lincolnshire, was living in Butt Lane, Asterby and she was still there at 78, in 1871.

Elizabeth Hatcliffe died, at 84, and was buried on 20 Feb 1877 at St Peter's, Asterby.

(Potential Issue: Although mine is not the only research to have come to the same conclusions (via), it would appear from DNA that this may not be the right marriage. Whilst there are (at time of writing) 18 DNA links to John Hatcliffe, there are exactly ZERO to Elizabeth Bratley. One would expect the number to be equal.)